Why is the voltage increased, when the loss-less lines are replaced by resistive lines?

At first sight it could be surprising that voltage is increased even though the current is decreased. This seeming contradiction is dissolved if the resistance of the voltage source is taken into account. The current is flowing through this resistance at the entrance, through the lines and the load. The total voltage of the source is distributed over these three resistors according to their resistance. Lines with resistance together with the load receive a larger part of the voltage than only the load with loss-less lines.
Leitungswiderstände plus Abschlußwiderstand erhalten einen größeren Spannungsanteil als der Abschlußwiderstand allein.
An example:

Why is the current increased?

At first sight it could be surprising that current is increased even though less voltage is available. This seeming contradiction is dissolved if as before the resistance of the voltage source is taken into account. The leakage current is an additional possibility for the current to reach the other line. Therefore the total resistance of the circuit has decreased in comparison with loss-less lines and the current has increased. A larger part of the total voltage is needed to drive the increased current through the internal resistor a smaller part is sufficient to drive the current through the parallel circuit.
An example:

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